2x-3/x^2-4-x-1/2x^2-5x+2=1/2X^2+3X-2

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Solution for 2x-3/x^2-4-x-1/2x^2-5x+2=1/2X^2+3X-2 equation: 



2x-3/x^2-4-x-1/2x^2-5x+2=1/2x^2+3x-2

We move all terms to the left:

2x-3/x^2-4-x-1/2x^2-5x+2-(1/2x^2+3x-2)=0



Domain of the equation: x^2!=0

x^2!=0/

x^2!=√0

x!=0

x∈R





Domain of the equation: 2x^2!=0

x^2!=0/2

x^2!=√0

x!=0

x∈R





Domain of the equation: 2x^2+3x-2)!=0

x∈R



We add all the numbers together, and all the variables

-4x-3/x^2-1/2x^2-(1/2x^2+3x-2)-2=0

We get rid of parentheses

-4x-3/x^2-1/2x^2-1/2x^2-3x+2-2=0

We calculate fractions

We do not support expression: x^4

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